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在R工作时分离所有包裹

在努力解决另一个问题时,我遇到了这个问题:

我可以删除所有R对象:

rm(list = ls(all = TRUE))

在工作会话期间是否有可以分离已安装软件包的等效命令?

> sessionInfo()
R version 2.12.2 (2011-02-25)
Platform: i386-pc-mingw32/i386 (32-bit)

locale:
[1] LC_COLLATE=English_United States.1252 
[2] LC_CTYPE=English_United States.1252   
[3] LC_MONETARY=English_United States.1252
[4] LC_NUMERIC=C                          
[5] LC_TIME=English_United States.1252    

attached base packages:
[1] stats     graphics  grDevices utils     datasets  methods   base 

需要(GGPLOT2)

Loading required package: ggplot2
Loading required package: reshape
Loading required package: plyr

Attaching package: 'reshape'

The following object(s) are masked from 'package:plyr':

    round_any

Loading required package: grid
Loading required package: proto

sessionInfo()

R version 2.12.2 (2011-02-25)
Platform: i386-pc-mingw32/i386 (32-bit)

locale:
[1] LC_COLLATE=English_United States.1252 
[2] LC_CTYPE=English_United States.1252   
[3] LC_MONETARY=English_United States.1252
[4] LC_NUMERIC=C                          
[5] LC_TIME=English_United States.1252    

attached base packages:
[1] grid      stats     graphics  grDevices utils     datasets  methods  
[8] base     

other attached packages:
[1] ggplot2_0.8.9 proto_0.3-9.1 reshape_0.8.4 plyr_1.4 

我试过这种方式,虽然它甚至不是一个全球性的解决方案:

pkg <- c("package:ggplot2_0.8.9", "package:proto_0.3-9.1", "package:reshape_0.8.4",  "package:plyr_1.4")

 detach(pkg, character.only = TRUE)

Error in detach(pkg, character.only = TRUE) : invalid 'name' argument
In addition: Warning message:
In if (is.na(pos)) stop("invalid 'name' argument") :
  the condition has length > 1 and only the first element will be used

我所要求的是全球性的:

  rm(list = ls(all = TRUE))

对于对象,期望它不会删除附加的基础包

谢谢;

83
John Clark

所以,有人应该简单地回答以下问题。

lapply(paste('package:',names(sessionInfo()$otherPkgs),sep=""),detach,character.only=TRUE,unload=TRUE)
78
mmfrgmpds

请试试这个:

detachAllPackages <- function() {

  basic.packages <- c("package:stats","package:graphics","package:grDevices","package:utils","package:datasets","package:methods","package:base")

  package.list <- search()[ifelse(unlist(gregexpr("package:",search()))==1,TRUE,FALSE)]

  package.list <- setdiff(package.list,basic.packages)

  if (length(package.list)>0)  for (package in package.list) detach(package, character.only=TRUE)

}

detachAllPackages()
48
mjaniec

你很亲密注意?detachdetach()的第一个参数name的说法是什么:

参数:

name: The object to detach.  Defaults to ‘search()[pos]’.  This can
      be an unquoted name or a character string but _not_ a
      character vector.  If a number is supplied this is taken as
      ‘pos’.

所以我们需要在pkg的每个元素上重复调用detach()一次。我们需要指定其他一些参数才能使其工作。第一个是character.only = TRUE,它允许函数假设name是一个字符串 - 如果没有它,它将无法工作。其次,我们也可能想要卸载任何相关的命名空间。这可以通过设置unload = TRUE来实现。所以解决方案是,例如:

pkg <- c("package:vegan","package:permute")
lapply(pkg, detach, character.only = TRUE, unload = TRUE)

这是一个完整的例子:

> require(vegan)
Loading required package: vegan
Loading required package: permute
This is vegan 2.0-0
> sessionInfo()
R version 2.13.1 Patched (2011-09-13 r57007)
Platform: x86_64-unknown-linux-gnu (64-bit)

locale:
 [1] LC_CTYPE=en_GB.utf8       LC_NUMERIC=C             
 [3] LC_TIME=en_GB.utf8        LC_COLLATE=en_GB.utf8    
 [5] LC_MONETARY=C             LC_MESSAGES=en_GB.utf8   
 [7] LC_PAPER=en_GB.utf8       LC_NAME=C                
 [9] LC_ADDRESS=C              LC_TELEPHONE=C           
[11] LC_MEASUREMENT=en_GB.utf8 LC_IDENTIFICATION=C      

attached base packages:
[1] stats     graphics  grDevices utils     datasets  methods  
[7] base     

other attached packages:
[1] vegan_2.0-0   permute_0.7-0

loaded via a namespace (and not attached):
[1] grid_2.13.1     lattice_0.19-33 tools_2.13.1   
> pkg <- c("package:vegan","package:permute")
> lapply(pkg, detach, character.only = TRUE, unload = TRUE)
[[1]]
NULL

[[2]]
NULL

> sessionInfo()
R version 2.13.1 Patched (2011-09-13 r57007)
Platform: x86_64-unknown-linux-gnu (64-bit)

locale:
 [1] LC_CTYPE=en_GB.utf8       LC_NUMERIC=C             
 [3] LC_TIME=en_GB.utf8        LC_COLLATE=en_GB.utf8    
 [5] LC_MONETARY=C             LC_MESSAGES=en_GB.utf8   
 [7] LC_PAPER=en_GB.utf8       LC_NAME=C                
 [9] LC_ADDRESS=C              LC_TELEPHONE=C           
[11] LC_MEASUREMENT=en_GB.utf8 LC_IDENTIFICATION=C      

attached base packages:
[1] stats     graphics  grDevices utils     datasets  methods  
[7] base     

loaded via a namespace (and not attached):
[1] grid_2.13.1     lattice_0.19-33 tools_2.13.1

如果要将其转换为函数,请研究sessionInfo()中的代码,以查看它如何标识它标记为“其他附加包:”。将这一点代码与上述想法结合在一个功能中,您就可以回家了。不过,我会把这一点留给你。

29
Gavin Simpson

基于Gavin的答案,但不是完整的功能将是这个序列:

sess.pkgs <- function (package = NULL) 
{   z <- list()
       if (is.null(package)) {
        package <- grep("^package:", search(), value = TRUE)
        keep <- sapply(package, function(x) x == "package:base" || 
            !is.null(attr(as.environment(x), "path")))
        package <- sub("^package:", "", package[keep])
    }
    pkgDesc <- lapply(package, packageDescription)
    if (length(package) == 0) 
        stop("no valid packages were specified")
    basePkgs <- sapply(pkgDesc, function(x) !is.null(x$Priority) && 
        x$Priority == "base")
    z$basePkgs <- package[basePkgs]
    if (any(!basePkgs)) {
        z$otherPkgs <-  package[!basePkgs]
    }
    z
}

lapply(paste("package:",sess.pkgs()$otherPkgs, sep=""), detach, 
                             character.only = TRUE, unload = TRUE)
8
42-

或者如果您有RStudio,只需取消选中Packages选项卡中的所有复选框即可分离

3
Ajay Ohri

如果你遇到类似命名函数的软件包相互冲突的问题,你总是可以引用你想要的函数的软件包的命名空间。

pkg_name::function_i_want()
0
M. Wood

大多数时候它是plyr vs dplyr问题。在代码的开头使用它:

detach("package:plyr", unload=TRUE)

因此,只要脚本运行,它就会清除plyr

0
Prashant