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使用SMTP从Python发送邮件

我正在使用以下方法使用SMTP从Python发送邮件。这是正确的使用方法还是我遗失了?

from smtplib import SMTP
import datetime

debuglevel = 0

smtp = SMTP()
smtp.set_debuglevel(debuglevel)
smtp.connect('YOUR.MAIL.SERVER', 26)
smtp.login('[email protected]', 'PASSWORD')

from_addr = "John Doe <[email protected]>"
to_addr = "[email protected]"

subj = "hello"
date = datetime.datetime.now().strftime( "%d/%m/%Y %H:%M" )

message_text = "Hello\nThis is a mail from your server\n\nBye\n"

msg = "From: %s\nTo: %s\nSubject: %s\nDate: %s\n\n%s" 
        % ( from_addr, to_addr, subj, date, message_text )

smtp.sendmail(from_addr, to_addr, msg)
smtp.quit()
103
Eli Bendersky

我使用的脚本非常相似;我在这里发布它作为如何使用电子邮件。*模块生成MIME消息的示例;因此可以轻松修改此脚本以附加图片等。

我依靠我的ISP添加日期时间标题。

我的ISP要求我使用安全的smtp连接发送邮件,我依靠smtplib模块(可从 http://www1.cs.columbia.edu/~db2501/ssmtplib.py 下载)

与在脚本中一样,用于在SMTP服务器上进行身份验证的用户名和密码(下面给出的虚拟值)在源中以纯文本形式显示。这是一个安全漏洞;但最好的选择取决于你需要多少小心(想要?)来保护这些。

=======================================

#! /usr/local/bin/python


SMTPserver = 'smtp.att.yahoo.com'
sender =     '[email protected]_email_domain.net'
destination = ['[email protected]_email_domain.com']

USERNAME = "USER_NAME_FOR_INTERNET_SERVICE_PROVIDER"
PASSWORD = "PASSWORD_INTERNET_SERVICE_PROVIDER"

# typical values for text_subtype are plain, html, xml
text_subtype = 'plain'


content="""\
Test message
"""

subject="Sent from Python"

import sys
import os
import re

from smtplib import SMTP_SSL as SMTP       # this invokes the secure SMTP protocol (port 465, uses SSL)
# from smtplib import SMTP                  # use this for standard SMTP protocol   (port 25, no encryption)

# old version
# from email.MIMEText import MIMEText
from email.mime.text import MIMEText

try:
    msg = MIMEText(content, text_subtype)
    msg['Subject']=       subject
    msg['From']   = sender # some SMTP servers will do this automatically, not all

    conn = SMTP(SMTPserver)
    conn.set_debuglevel(False)
    conn.login(USERNAME, PASSWORD)
    try:
        conn.sendmail(sender, destination, msg.as_string())
    finally:
        conn.quit()

except:
    sys.exit( "mail failed; %s" % "CUSTOM_ERROR" ) # give an error message
105
Vincent Marchetti

我常用的方法......差别不大但有点不同

import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText

msg = MIMEMultipart()
msg['From'] = '[email protected]'
msg['To'] = '[email protected]'
msg['Subject'] = 'simple email in python'
message = 'here is the email'
msg.attach(MIMEText(message))

mailserver = smtplib.SMTP('smtp.gmail.com',587)
# identify ourselves to smtp gmail client
mailserver.ehlo()
# secure our email with tls encryption
mailserver.starttls()
# re-identify ourselves as an encrypted connection
mailserver.ehlo()
mailserver.login('[email protected]', 'mypassword')

mailserver.sendmail('[email protected]','[email protected]',msg.as_string())

mailserver.quit()

而已

78
madman2890

此外,如果您想使用TLS而不是SSL执行smtp auth,那么您只需更改端口(使用587)并执行smtp.starttls()。这对我有用:

...
smtp.connect('YOUR.MAIL.SERVER', 587)
smtp.ehlo()
smtp.starttls()
smtp.ehlo()
smtp.login('[email protected]', 'PASSWORD')
...
21
mandric

我看到的主要问题是你没有处理任何错误:.login()和.sendmail()都记录了他们可以抛出的异常,似乎.connect()必须有一些方法来表明它是无法连接 - 可能是底层套接字代码抛出的异常。

6
pjz

以下代码对我来说很好:

import smtplib

to = '[email protected]'
gmail_user = '[email protected]'
gmail_pwd = 'yourpassword'
smtpserver = smtplib.SMTP("smtp.gmail.com",587)
smtpserver.ehlo()
smtpserver.starttls()
smtpserver.ehlo() # extra characters to permit edit
smtpserver.login(gmail_user, gmail_pwd)
header = 'To:' + to + '\n' + 'From: ' + gmail_user + '\n' + 'Subject:testing \n'
print header
msg = header + '\n this is test msg from mkyong.com \n\n'
smtpserver.sendmail(gmail_user, to, msg)
print 'done!'
smtpserver.quit()

参考: http://www.mkyong.com/python/how-do-send-email-in-python-via-smtplib/

5
Abdul Majeed

那这个呢?

import smtplib

SERVER = "localhost"

FROM = "[email protected]"
TO = ["[email protected]"] # must be a list

SUBJECT = "Hello!"

TEXT = "This message was sent with Python's smtplib."

# Prepare actual message

message = """\
From: %s
To: %s
Subject: %s

%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)

# Send the mail

server = smtplib.SMTP(SERVER)
server.sendmail(FROM, TO, message)
server.quit()
5
Satish

确保没有任何阻止SMTP的防火墙。我第一次尝试发送电子邮件时,它被Windows防火墙和迈克菲阻止 - 永远都找到了它们。

5
Mark Ransom

您应该确保以正确的格式格式化日期 - RFC2822

3
Douglas Leeder

我使用SMTP发送邮件的示例代码。

import smtplib, ssl

smtp_server = "smtp.gmail.com"
port = 587  # For starttls
sender_email = "[email protected]"
receiver_email = "[email protected]"
password = "<your password here>"
message = """ Subject: Hi there

This message is sent from Python."""


# Create a secure SSL context
context = ssl.create_default_context()

# Try to log in to server and send email
server = smtplib.SMTP(smtp_server,port)

try:
    server.ehlo() # Can be omitted
    server.starttls(context=context) # Secure the connection
    server.ehlo() # Can be omitted
    server.login(sender_email, password)
    server.sendmail(sender_email, receiver_email, message)
except Exception as e:
    # Print any error messages to stdout
    print(e)
finally:
    server.quit()
2
Hariharan AR

看到所有那些长长的答案?请允许我通过几行来完成所有活动。

导入和连接:

import yagmail
yag = yagmail.SMTP('[email protected]', Host = 'YOUR.MAIL.SERVER', port = 26)

然后它只是一个单行:

yag.send('[email protected]', 'hello', 'Hello\nThis is a mail from your server\n\nBye\n')

它实际上会在超出范围时关闭(或者可以手动关闭)。此外,它允许您在密钥环中注册您的用户名,这样您就不必在脚本中写出您的密码(在写yagmail之前,它确实困扰我!)

对于软件包/安装,提示和技巧,请查看 gitpip ,可用于Python 2和3。

2
PascalVKooten

这是Python 3.x的一个工作示例

#!/usr/bin/env python3

from email.message import EmailMessage
from getpass import getpass
from smtplib import SMTP_SSL
from sys import exit

smtp_server = 'smtp.gmail.com'
username = '[email protected]'
password = getpass('Enter Gmail password: ')

sender = '[email protected]'
destination = '[email protected]'
subject = 'Sent from Python 3.x'
content = 'Hello! This was sent to you via Python 3.x!'

# Create a text/plain message
msg = EmailMessage()
msg.set_content(content)

msg['Subject'] = subject
msg['From'] = sender
msg['To'] = destination

try:
    s = SMTP_SSL(smtp_server)
    s.login(username, password)
    try:
        s.send_message(msg)
    finally:
        s.quit()

except Exception as E:
    exit('Mail failed: {}'.format(str(E)))
0
Mark

你可以这样做

import smtplib
from email.mime.text import MIMEText
from email.header import Header


server = smtplib.SMTP('mail.servername.com', 25)
server.ehlo()
server.starttls()

server.login('username', 'password')
from = '[email protected]'
to = '[email protected]'
body = 'That A Message For My Girl Friend For tell Him If We will go to eat Something This Nigth'
subject = 'Invite to A Diner'
msg = MIMEText(body,'plain','utf-8')
msg['Subject'] = Header(subject, 'utf-8')
msg['From'] = Header(from, 'utf-8')
msg['To'] = Header(to, 'utf-8')
message = msg.as_string()
server.sendmail(from, to, message)
0
Skiller Dz